class Solution:
def isAnagram(self, s: str, t: str) -> bool:
s = list(s)
t = list(t)
s.sort()
t.sort()
return s==t
1445B - Elimination | 1656C - Make Equal With Mod |
567A - Lineland Mail | 1553A - Digits Sum |
1359B - New Theatre Square | 766A - Mahmoud and Longest Uncommon Subsequence |
701B - Cells Not Under Attack | 702A - Maximum Increase |
1656D - K-good | 1426A - Floor Number |
876A - Trip For Meal | 1326B - Maximums |
1635C - Differential Sorting | 961A - Tetris |
1635B - Avoid Local Maximums | 20A - BerOS file system |
1637A - Sorting Parts | 509A - Maximum in Table |
1647C - Madoka and Childish Pranks | 689B - Mike and Shortcuts |
379B - New Year Present | 1498A - GCD Sum |
1277C - As Simple as One and Two | 1301A - Three Strings |
460A - Vasya and Socks | 1624C - Division by Two and Permutation |
1288A - Deadline | 1617A - Forbidden Subsequence |
914A - Perfect Squares | 873D - Merge Sort |